Base | Representation |
---|---|
bin | 1100001010111001000011… |
… | …0001000010100100000000 |
3 | 1202101020100110012211022001 |
4 | 3002232100301002210000 |
5 | 3223214300441323241 |
6 | 44243132351553344 |
7 | 2550522616321600 |
oct | 302562061024400 |
9 | 52336313184261 |
10 | 13381251901696 |
11 | 4299a58939378 |
12 | 160146222b854 |
13 | 760b010b6163 |
14 | 3439282a2c00 |
15 | 1831251a3431 |
hex | c2b90c42900 |
13381251901696 has 54 divisors (see below), whose sum is σ = 31071087731670. Its totient is φ = 5734822238208.
The previous prime is 13381251901631. The next prime is 13381251901697. The reversal of 13381251901696 is 69610915218331.
It can be written as a sum of positive squares in only one way, i.e., 9244421335296 + 4136830566400 = 3040464^2 + 2033920^2 .
It is a super-3 number, since 3×133812519016963 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13381251901697) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 533360061 + ... + 533385148.
Almost surely, 213381251901696 is an apocalyptic number.
13381251901696 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
13381251901696 is an abundant number, since it is smaller than the sum of its proper divisors (17689835829974).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13381251901696 is an equidigital number, since it uses as much as digits as its factorization.
13381251901696 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1066745239 (or 1066745218 counting only the distinct ones).
The product of its (nonzero) digits is 2099520, while the sum is 55.
The spelling of 13381251901696 in words is "thirteen trillion, three hundred eighty-one billion, two hundred fifty-one million, nine hundred one thousand, six hundred ninety-six".
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