Base | Representation |
---|---|
bin | 100111111000111… |
… | …0010100001001111 |
3 | 10110021112102001001 |
4 | 1033301302201033 |
5 | 10220120431142 |
6 | 340451401131 |
7 | 45111440362 |
oct | 11761624117 |
9 | 3407472031 |
10 | 1338452047 |
11 | 627580919 |
12 | 3142b31a7 |
13 | 1843ac07a |
14 | c9a900d9 |
15 | 7c7885b7 |
hex | 4fc7284f |
1338452047 has 2 divisors, whose sum is σ = 1338452048. Its totient is φ = 1338452046.
The previous prime is 1338452039. The next prime is 1338452077. The reversal of 1338452047 is 7402548331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1338452047 - 23 = 1338452039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1338451997 and 1338452015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1338452077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669226023 + 669226024.
It is an arithmetic number, because the mean of its divisors is an integer number (669226024).
Almost surely, 21338452047 is an apocalyptic number.
1338452047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1338452047 is an equidigital number, since it uses as much as digits as its factorization.
1338452047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 37.
The square root of 1338452047 is about 36584.8608990112. The cubic root of 1338452047 is about 1102.0490860906.
The spelling of 1338452047 in words is "one billion, three hundred thirty-eight million, four hundred fifty-two thousand, forty-seven".
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