Base | Representation |
---|---|
bin | 111110010101101000… |
… | …1000111000001110100 |
3 | 110210112121211010001001 |
4 | 1330223101013001310 |
5 | 4143131143013300 |
6 | 141255440213044 |
7 | 12446264206306 |
oct | 1745321070164 |
9 | 423477733031 |
10 | 133869891700 |
11 | 51857078036 |
12 | 21b4090a184 |
13 | c81587038c |
14 | 669d431976 |
15 | 373798816a |
hex | 1f2b447074 |
133869891700 has 18 divisors (see below), whose sum is σ = 290497665206. Its totient is φ = 53547956640.
The previous prime is 133869891667. The next prime is 133869891731. The reversal of 133869891700 is 7198968331.
It can be written as a sum of positive squares in 3 ways, for example, as 1320014224 + 132549877476 = 36332^2 + 364074^2 .
It is a super-2 number, since 2×1338698917002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 669349359 + ... + 669349558.
Almost surely, 2133869891700 is an apocalyptic number.
133869891700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133869891700 is an abundant number, since it is smaller than the sum of its proper divisors (156627773506).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133869891700 is a wasteful number, since it uses less digits than its factorization.
133869891700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1338698931 (or 1338698924 counting only the distinct ones).
The product of its (nonzero) digits is 1959552, while the sum is 55.
The spelling of 133869891700 in words is "one hundred thirty-three billion, eight hundred sixty-nine million, eight hundred ninety-one thousand, seven hundred".
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