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133869891700 = 22521338698917
BaseRepresentation
bin111110010101101000…
…1000111000001110100
3110210112121211010001001
41330223101013001310
54143131143013300
6141255440213044
712446264206306
oct1745321070164
9423477733031
10133869891700
1151857078036
1221b4090a184
13c81587038c
14669d431976
15373798816a
hex1f2b447074

133869891700 has 18 divisors (see below), whose sum is σ = 290497665206. Its totient is φ = 53547956640.

The previous prime is 133869891667. The next prime is 133869891731. The reversal of 133869891700 is 7198968331.

It can be written as a sum of positive squares in 3 ways, for example, as 1320014224 + 132549877476 = 36332^2 + 364074^2 .

It is a super-2 number, since 2×1338698917002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 669349359 + ... + 669349558.

Almost surely, 2133869891700 is an apocalyptic number.

133869891700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133869891700 is an abundant number, since it is smaller than the sum of its proper divisors (156627773506).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133869891700 is a wasteful number, since it uses less digits than its factorization.

133869891700 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1338698931 (or 1338698924 counting only the distinct ones).

The product of its (nonzero) digits is 1959552, while the sum is 55.

The spelling of 133869891700 in words is "one hundred thirty-three billion, eight hundred sixty-nine million, eight hundred ninety-one thousand, seven hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1338698917 2677397834 5354795668 6693494585 13386989170 26773978340 33467472925 66934945850 133869891700