1338765926400 has 2016 divisors, whose sum is σ = 5887020036960. Its totient is φ = 300987187200.

The previous prime is 1338765926363. The next prime is 1338765926417. The reversal of 1338765926400 is 46295678331.

1338765926400 is a `hidden beast` number, since 1 + 3 + 3 + 8 + 7 + 6 + 592 + 6 + 40 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2016).

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 21946982370 + ... + 21946982430.

It is a 1-persistent number, because it is pandigital, but 2⋅1338765926400 = 2677531852800 is not.

Almost surely, 2^{1338765926400} is an apocalyptic number.

1338765926400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1338765926400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2943510018480).

1338765926400 is an abundant number, since it is smaller than the sum of its proper divisors (4548254110560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1338765926400 is an frugal number, since it uses more digits than its factorization.

1338765926400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132 (or 78 counting only the distinct ones).

The product of its (nonzero) digits is 6531840, while the sum is 54.

The spelling of 1338765926400 in words is "one trillion, three hundred thirty-eight billion, seven hundred sixty-five million, nine hundred twenty-six thousand, four hundred".