1339402111 has 2 divisors, whose sum is σ = 1339402112. Its totient is φ = 1339402110.

The previous prime is 1339402073. The next prime is 1339402117. The reversal of 1339402111 is 1112049331.

It is a strong prime.

It is an emirp because it is prime and its reverse (1112049331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1339402111 - 2¹³ = 1339393919 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1339402117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669701055 + 669701056.

It is an arithmetic number, because the mean of its divisors is an integer number (669701056).

Almost surely, 2^1339402111 is an apocalyptic number.

1339402111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1339402111 is an equidigital number, since it uses as much as digits as its factorization.

1339402111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1339402111 is about 36597.8429828863. The cubic root of 1339402111 is about 1102.3097776685.

The spelling of 1339402111 in words is "one billion, three hundred thirty-nine million, four hundred two thousand, one hundred eleven".