13400044013 has 2 divisors, whose sum is σ = 13400044014. Its totient is φ = 13400044012.

The previous prime is 13400044001. The next prime is 13400044039. The reversal of 13400044013 is 31044000431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8328752644 + 5071291369 = 91262^2 + 71213^2 .

It is a cyclic number.

It is not a de Polignac number, because 13400044013 - 2⁴ = 13400043997 is a prime.

It is a super-2 number, since 2×13400044013² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13400044813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700022006 + 6700022007.

It is an arithmetic number, because the mean of its divisors is an integer number (6700022007).

Almost surely, 2^13400044013 is an apocalyptic number.

It is an amenable number.

13400044013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400044013 is an equidigital number, since it uses as much as digits as its factorization.

13400044013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13400044013 its reverse (31044000431), we get a palindrome (44444044444).

The spelling of 13400044013 in words is "thirteen billion, four hundred million, forty-four thousand, thirteen".