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13400045335559 is a prime number
BaseRepresentation
bin1100001011111111000011…
…1100010011010000000111
31202110000212012101011222002
43002333300330103100013
53224021243101214214
644255521300255515
72552056421012141
oct302776074232007
952400765334862
1013400045335559
1142a6a222873a3
1216050280a159b
1376280780aa1c
143447cc229c91
151838750381de
hexc2ff0f13407

13400045335559 has 2 divisors, whose sum is σ = 13400045335560. Its totient is φ = 13400045335558.

The previous prime is 13400045335541. The next prime is 13400045335673. The reversal of 13400045335559 is 95553354000431.

13400045335559 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13400045335559 is a prime.

It is a super-2 number, since 2×134000453355592 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13400048335559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700022667779 + 6700022667780.

It is an arithmetic number, because the mean of its divisors is an integer number (6700022667780).

Almost surely, 213400045335559 is an apocalyptic number.

13400045335559 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400045335559 is an equidigital number, since it uses as much as digits as its factorization.

13400045335559 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2430000, while the sum is 47.

The spelling of 13400045335559 in words is "thirteen trillion, four hundred billion, forty-five million, three hundred thirty-five thousand, five hundred fifty-nine".