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134001066522341 is a prime number
BaseRepresentation
bin11110011101111110001101…
…111110000011011011100101
3122120110101011201112221022102
4132131332031332003123211
5120030433141012203331
61152555123511141445
740140154230046304
oct3635761576033345
9576411151487272
10134001066522341
1139773595718917
121304237a074885
1359a032830c715
14251398700443b
151075a1dec54cb
hex79df8df836e5

134001066522341 has 2 divisors, whose sum is σ = 134001066522342. Its totient is φ = 134001066522340.

The previous prime is 134001066522307. The next prime is 134001066522371. The reversal of 134001066522341 is 143225660100431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131646824325025 + 2354242197316 = 11473745^2 + 1534354^2 .

It is a cyclic number.

It is not a de Polignac number, because 134001066522341 - 242 = 129603020011237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134001066522295 and 134001066522304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134001066522371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000533261170 + 67000533261171.

It is an arithmetic number, because the mean of its divisors is an integer number (67000533261171).

Almost surely, 2134001066522341 is an apocalyptic number.

It is an amenable number.

134001066522341 is a deficient number, since it is larger than the sum of its proper divisors (1).

134001066522341 is an equidigital number, since it uses as much as digits as its factorization.

134001066522341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 134001066522341 in words is "one hundred thirty-four trillion, one billion, sixty-six million, five hundred twenty-two thousand, three hundred forty-one".