Base | Representation |
---|---|
bin | 11110011101111110001101… |
… | …111110000011011011100101 |
3 | 122120110101011201112221022102 |
4 | 132131332031332003123211 |
5 | 120030433141012203331 |
6 | 1152555123511141445 |
7 | 40140154230046304 |
oct | 3635761576033345 |
9 | 576411151487272 |
10 | 134001066522341 |
11 | 39773595718917 |
12 | 1304237a074885 |
13 | 59a032830c715 |
14 | 251398700443b |
15 | 1075a1dec54cb |
hex | 79df8df836e5 |
134001066522341 has 2 divisors, whose sum is σ = 134001066522342. Its totient is φ = 134001066522340.
The previous prime is 134001066522307. The next prime is 134001066522371. The reversal of 134001066522341 is 143225660100431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131646824325025 + 2354242197316 = 11473745^2 + 1534354^2 .
It is a cyclic number.
It is not a de Polignac number, because 134001066522341 - 242 = 129603020011237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134001066522295 and 134001066522304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134001066522371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000533261170 + 67000533261171.
It is an arithmetic number, because the mean of its divisors is an integer number (67000533261171).
Almost surely, 2134001066522341 is an apocalyptic number.
It is an amenable number.
134001066522341 is a deficient number, since it is larger than the sum of its proper divisors (1).
134001066522341 is an equidigital number, since it uses as much as digits as its factorization.
134001066522341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 134001066522341 in words is "one hundred thirty-four trillion, one billion, sixty-six million, five hundred twenty-two thousand, three hundred forty-one".
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