Base | Representation |
---|---|
bin | 11000111101011011… |
… | …00010000110111101 |
3 | 1021120212202101022122 |
4 | 30132231202012331 |
5 | 204420414421212 |
6 | 10053403452325 |
7 | 653032301666 |
oct | 143655420675 |
9 | 37525671278 |
10 | 13400154557 |
11 | 57570464a9 |
12 | 271b8270a5 |
13 | 135726874a |
14 | 91197036d |
15 | 536646272 |
hex | 31eb621bd |
13400154557 has 2 divisors, whose sum is σ = 13400154558. Its totient is φ = 13400154556.
The previous prime is 13400154479. The next prime is 13400154583. The reversal of 13400154557 is 75545100431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10582031161 + 2818123396 = 102869^2 + 53086^2 .
It is a cyclic number.
It is not a de Polignac number, because 13400154557 - 212 = 13400150461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13400154587) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700077278 + 6700077279.
It is an arithmetic number, because the mean of its divisors is an integer number (6700077279).
Almost surely, 213400154557 is an apocalyptic number.
It is an amenable number.
13400154557 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400154557 is an equidigital number, since it uses as much as digits as its factorization.
13400154557 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42000, while the sum is 35.
Adding to 13400154557 its reverse (75545100431), we get a palindrome (88945254988).
The spelling of 13400154557 in words is "thirteen billion, four hundred million, one hundred fifty-four thousand, five hundred fifty-seven".
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