13400300343041 has 2 divisors, whose sum is σ = 13400300343042. Its totient is φ = 13400300343040.

The previous prime is 13400300343011. The next prime is 13400300343043. The reversal of 13400300343041 is 14034300300431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12767193680641 + 633106662400 = 3573121^2 + 795680^2 .

It is a cyclic number.

It is not a de Polignac number, because 13400300343041 - 2²⁶ = 13400233234177 is a prime.

Together with 13400300343043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13400300343041.

It is not a weakly prime, because it can be changed into another prime (13400300343043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700150171520 + 6700150171521.

It is an arithmetic number, because the mean of its divisors is an integer number (6700150171521).

Almost surely, 2^{13400300343041} is an apocalyptic number.

It is an amenable number.

13400300343041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400300343041 is an equidigital number, since it uses as much as digits as its factorization.

13400300343041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 13400300343041 its reverse (14034300300431), we get a palindrome (27434600643472).

The spelling of 13400300343041 in words is "thirteen trillion, four hundred billion, three hundred million, three hundred forty-three thousand, forty-one".