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134004632411207 is a prime number
BaseRepresentation
bin11110011110000001100010…
…100000110101110001000111
3122120110201101020101212020102
4132132001202200311301013
5120031012441344124312
61153000513412354315
740140341466440615
oct3636014240656107
9576421336355212
10134004632411207
1139775055558a08
1213042bb431599b
1359a077600852c
142513c048346b5
151075b7c099ec2
hex79e062835c47

134004632411207 has 2 divisors, whose sum is σ = 134004632411208. Its totient is φ = 134004632411206.

The previous prime is 134004632411189. The next prime is 134004632411401. The reversal of 134004632411207 is 702114236400431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134004632411207 - 212 = 134004632407111 is a prime.

It is a super-5 number, since 5×1340046324112075 (a number of 72 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134004632411107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67002316205603 + 67002316205604.

It is an arithmetic number, because the mean of its divisors is an integer number (67002316205604).

Almost surely, 2134004632411207 is an apocalyptic number.

134004632411207 is a deficient number, since it is larger than the sum of its proper divisors (1).

134004632411207 is an equidigital number, since it uses as much as digits as its factorization.

134004632411207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96768, while the sum is 38.

Adding to 134004632411207 its reverse (702114236400431), we get a palindrome (836118868811638).

The spelling of 134004632411207 in words is "one hundred thirty-four trillion, four billion, six hundred thirty-two million, four hundred eleven thousand, two hundred seven".