Base | Representation |
---|---|
bin | 1100001100000000111011… |
… | …0011001010000100000110 |
3 | 1202110002011002221112102001 |
4 | 3003000032303022010012 |
5 | 3224023304320130420 |
6 | 44300043112535514 |
7 | 2552105012526040 |
oct | 303001663120406 |
9 | 52402132845361 |
10 | 13400546255110 |
11 | 42a715a0116a3 |
12 | 16051479b159a |
13 | 762887525521 |
14 | 344838980a90 |
15 | 1838a3ed3b0a |
hex | c300ecca106 |
13400546255110 has 32 divisors (see below), whose sum is σ = 27568653926400. Its totient is φ = 4594170349152.
The previous prime is 13400546255027. The next prime is 13400546255113. The reversal of 13400546255110 is 1155264500431.
It is a super-3 number, since 3×134005462551103 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 13400546255110.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13400546255113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5233734 + ... + 7361593.
It is an arithmetic number, because the mean of its divisors is an integer number (861520435200).
Almost surely, 213400546255110 is an apocalyptic number.
13400546255110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13400546255110 is an abundant number, since it is smaller than the sum of its proper divisors (14168107671290).
13400546255110 is a wasteful number, since it uses less digits than its factorization.
13400546255110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12610540.
The product of its (nonzero) digits is 72000, while the sum is 37.
The spelling of 13400546255110 in words is "thirteen trillion, four hundred billion, five hundred forty-six million, two hundred fifty-five thousand, one hundred ten".
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