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1340103157 is a prime number
BaseRepresentation
bin100111111100000…
…0101100111110101
310110101122021221021
41033320011213311
510221031300112
6340551021141
745131455201
oct11770054765
93411567837
101340103157
116284a9378
1231496a7b1
13184839763
14c9d9db01
157c9b2907
hex4fe059f5

1340103157 has 2 divisors, whose sum is σ = 1340103158. Its totient is φ = 1340103156.

The previous prime is 1340103133. The next prime is 1340103187. The reversal of 1340103157 is 7513010431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1061847396 + 278255761 = 32586^2 + 16681^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340103157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340103187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051578 + 670051579.

It is an arithmetic number, because the mean of its divisors is an integer number (670051579).

Almost surely, 21340103157 is an apocalyptic number.

It is an amenable number.

1340103157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340103157 is an equidigital number, since it uses as much as digits as its factorization.

1340103157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 1340103157 is about 36607.4194255755. The cubic root of 1340103157 is about 1102.5020612429.

Adding to 1340103157 its reverse (7513010431), we get a palindrome (8853113588).

The spelling of 1340103157 in words is "one billion, three hundred forty million, one hundred three thousand, one hundred fifty-seven".