Base | Representation |
---|---|
bin | 11110011110000111110111… |
… | …101100000000110010011110 |
3 | 122120111100220222110212020210 |
4 | 132132013313230000302132 |
5 | 120031120402102044124 |
6 | 1153004000122553250 |
7 | 40141002111106521 |
oct | 3636076754006236 |
9 | 576440828425223 |
10 | 134011430112414 |
11 | 39777a2369a498 |
12 | 13044390968826 |
13 | 59a12ba430a3a |
14 | 251428b570bb8 |
15 | 1075e28c53a29 |
hex | 79e1f7b00c9e |
134011430112414 has 32 divisors (see below), whose sum is σ = 268760545361280. Its totient is φ = 44547609002400.
The previous prime is 134011430112407. The next prime is 134011430112421. The reversal of 134011430112414 is 414211034110431.
It is an interprime number because it is at equal distance from previous prime (134011430112407) and next prime (134011430112421).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3259452 + ... + 16692719.
It is an arithmetic number, because the mean of its divisors is an integer number (8398767042540).
Almost surely, 2134011430112414 is an apocalyptic number.
134011430112414 is an abundant number, since it is smaller than the sum of its proper divisors (134749115248866).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134011430112414 is a wasteful number, since it uses less digits than its factorization.
134011430112414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19955256.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 134011430112414 its reverse (414211034110431), we get a palindrome (548222464222845).
The spelling of 134011430112414 in words is "one hundred thirty-four trillion, eleven billion, four hundred thirty million, one hundred twelve thousand, four hundred fourteen".
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