134011531 has 2 divisors, whose sum is σ = 134011532. Its totient is φ = 134011530.

The previous prime is 134011529. The next prime is 134011567. The reversal of 134011531 is 135110431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134011531 - 2¹ = 134011529 is a prime.

It is a super-2 number, since 2×134011531² = 35918180881927922, which contains 22 as substring.

Together with 134011529, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134011499 and 134011508.

It is not a weakly prime, because it can be changed into another prime (134011511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005765 + 67005766.

It is an arithmetic number, because the mean of its divisors is an integer number (67005766).

Almost surely, 2^134011531 is an apocalyptic number.

134011531 is a deficient number, since it is larger than the sum of its proper divisors (1).

134011531 is an equidigital number, since it uses as much as digits as its factorization.

134011531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 134011531 is about 11576.3349554166. The cubic root of 134011531 is about 511.7376725733.

Adding to 134011531 its reverse (135110431), we get a palindrome (269121962).

The spelling of 134011531 in words is "one hundred thirty-four million, eleven thousand, five hundred thirty-one".