Base | Representation |
---|---|
bin | 10011100000000101011… |
… | …011111011000100000000 |
3 | 11202010002100002112121002 |
4 | 103200011123323010000 |
5 | 133424031434032430 |
6 | 2503350523551132 |
7 | 165551306366366 |
oct | 23400533730400 |
9 | 4663070075532 |
10 | 1340121002240 |
11 | 477384406a89 |
12 | 19788398b4a8 |
13 | 994b0264b57 |
14 | 48c0dc53636 |
15 | 24cd635e845 |
hex | 138056fb100 |
1340121002240 has 36 divisors (see below), whose sum is σ = 3210008591244. Its totient is φ = 536048400384.
The previous prime is 1340121002183. The next prime is 1340121002257. The reversal of 1340121002240 is 422001210431.
It can be written as a sum of positive squares in 2 ways, for example, as 711310065664 + 628810936576 = 843392^2 + 792976^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523483487 + ... + 523486046.
Almost surely, 21340121002240 is an apocalyptic number.
1340121002240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1340121002240 is an abundant number, since it is smaller than the sum of its proper divisors (1869887589004).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340121002240 is an equidigital number, since it uses as much as digits as its factorization.
1340121002240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1046969554 (or 1046969540 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1340121002240 its reverse (422001210431), we get a palindrome (1762122212671).
The spelling of 1340121002240 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, two thousand, two hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •