1340121130421 has 2 divisors, whose sum is σ = 1340121130422. Its totient is φ = 1340121130420.

The previous prime is 1340121130417. The next prime is 1340121130423. The reversal of 1340121130421 is 1240311210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 888824700625 + 451296429796 = 942775^2 + 671786^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340121130421 - 2² = 1340121130417 is a prime.

Together with 1340121130423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340121130423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060565210 + 670060565211.

It is an arithmetic number, because the mean of its divisors is an integer number (670060565211).

Almost surely, 2^{1340121130421} is an apocalyptic number.

It is an amenable number.

1340121130421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121130421 is an equidigital number, since it uses as much as digits as its factorization.

1340121130421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1340121130421 its reverse (1240311210431), we get a palindrome (2580432340852).

The spelling of 1340121130421 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, one hundred thirty thousand, four hundred twenty-one".