Base | Representation |
---|---|
bin | 100111111100000… |
… | …1010000100111001 |
3 | 10110101200012221222 |
4 | 1033320022010321 |
5 | 10221032341101 |
6 | 340551241425 |
7 | 45131562323 |
oct | 11770120471 |
9 | 3411605858 |
10 | 1340121401 |
11 | 628511053 |
12 | 314979275 |
13 | 184844b58 |
14 | c9da6613 |
15 | 7c9b801b |
hex | 4fe0a139 |
1340121401 has 2 divisors, whose sum is σ = 1340121402. Its totient is φ = 1340121400.
The previous prime is 1340121397. The next prime is 1340121421. The reversal of 1340121401 is 1041210431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1315875625 + 24245776 = 36275^2 + 4924^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340121401 - 22 = 1340121397 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340121401.
It is not a weakly prime, because it can be changed into another prime (1340121421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060700 + 670060701.
It is an arithmetic number, because the mean of its divisors is an integer number (670060701).
Almost surely, 21340121401 is an apocalyptic number.
It is an amenable number.
1340121401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340121401 is an equidigital number, since it uses as much as digits as its factorization.
1340121401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
The square root of 1340121401 is about 36607.6686091862. The cubic root of 1340121401 is about 1102.5070643295.
Adding to 1340121401 its reverse (1041210431), we get a palindrome (2381331832).
The spelling of 1340121401 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, four hundred one".
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