Base | Representation |
---|---|
bin | 11000111101100011… |
… | …00101110111110000 |
3 | 1021120221202102211120 |
4 | 30132301211313300 |
5 | 204421202443134 |
6 | 10053442342240 |
7 | 653044323000 |
oct | 143661456760 |
9 | 37527672746 |
10 | 13401218544 |
11 | 575770292a |
12 | 272005a980 |
13 | 135754bb1c |
14 | 911b6a000 |
15 | 5367a6649 |
hex | 31ec65df0 |
13401218544 has 80 divisors (see below), whose sum is σ = 40373011200. Its totient is φ = 3828914880.
The previous prime is 13401218513. The next prime is 13401218569. The reversal of 13401218544 is 44581210431.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 390522 + ... + 423449.
It is an arithmetic number, because the mean of its divisors is an integer number (504662640).
Almost surely, 213401218544 is an apocalyptic number.
13401218544 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13401218544 is an abundant number, since it is smaller than the sum of its proper divisors (26971792656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401218544 is an equidigital number, since it uses as much as digits as its factorization.
13401218544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 814003 (or 813983 counting only the distinct ones).
The product of its (nonzero) digits is 15360, while the sum is 33.
Adding to 13401218544 its reverse (44581210431), we get a palindrome (57982428975).
The spelling of 13401218544 in words is "thirteen billion, four hundred one million, two hundred eighteen thousand, five hundred forty-four".
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