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1340122010207 is a prime number
BaseRepresentation
bin10011100000000101011…
…111110001001001011111
311202010002101222202021012
4103200011133301021133
5133424032213311312
62503351001325435
7165551321065151
oct23400537611137
94663071882235
101340122010207
11477384a35312
1219788419687b
13994b0528896
1448c10036ad1
1524cd64ad322
hex138057f125f

1340122010207 has 2 divisors, whose sum is σ = 1340122010208. Its totient is φ = 1340122010206.

The previous prime is 1340122010203. The next prime is 1340122010273. The reversal of 1340122010207 is 7020102210431.

It is a weak prime.

It is an emirp because it is prime and its reverse (7020102210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340122010207 - 22 = 1340122010203 is a prime.

It is a super-2 number, since 2×13401220102072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340122010203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670061005103 + 670061005104.

It is an arithmetic number, because the mean of its divisors is an integer number (670061005104).

Almost surely, 21340122010207 is an apocalyptic number.

1340122010207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340122010207 is an equidigital number, since it uses as much as digits as its factorization.

1340122010207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 23.

Adding to 1340122010207 its reverse (7020102210431), we get a palindrome (8360224220638).

The spelling of 1340122010207 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, ten thousand, two hundred seven".