13401221020301 has 2 divisors, whose sum is σ = 13401221020302. Its totient is φ = 13401221020300.

The previous prime is 13401221020279. The next prime is 13401221020303. The reversal of 13401221020301 is 10302012210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9259690764676 + 4141530255625 = 3042974^2 + 2035075^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401221020301 is a prime.

Together with 13401221020303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401221020303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610510150 + 6700610510151.

It is an arithmetic number, because the mean of its divisors is an integer number (6700610510151).

Almost surely, 2^{13401221020301} is an apocalyptic number.

It is an amenable number.

13401221020301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401221020301 is an equidigital number, since it uses as much as digits as its factorization.

13401221020301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13401221020301 its reverse (10302012210431), we get a palindrome (23703233230732).

The spelling of 13401221020301 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty thousand, three hundred one".