13401221023231 has 2 divisors, whose sum is σ = 13401221023232. Its totient is φ = 13401221023230.

The previous prime is 13401221023217. The next prime is 13401221023247. The reversal of 13401221023231 is 13232012210431.

13401221023231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13401221023231 - 2⁴¹ = 11202197767679 is a prime.

It is a super-2 number, since 2×13401221023231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13401221023196 and 13401221023205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401221023261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610511615 + 6700610511616.

It is an arithmetic number, because the mean of its divisors is an integer number (6700610511616).

Almost surely, 2^{13401221023231} is an apocalyptic number.

13401221023231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401221023231 is an equidigital number, since it uses as much as digits as its factorization.

13401221023231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13401221023231 its reverse (13232012210431), we get a palindrome (26633233233662).

The spelling of 13401221023231 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, two hundred thirty-one".