13401231320230 has 16 divisors (see below), whose sum is σ = 25977771482544. Its totient is φ = 4948146948960.

The previous prime is 13401231320221. The next prime is 13401231320249. The reversal of 13401231320230 is 3202313210431.

It is a junction number, because it is equal to n+sod(n) for n = 13401231320195 and 13401231320204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51543197256 + ... + 51543197515.

It is an arithmetic number, because the mean of its divisors is an integer number (1623610717659).

Almost surely, 2^{13401231320230} is an apocalyptic number.

13401231320230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13401231320230 is a deficient number, since it is larger than the sum of its proper divisors (12576540162314).

13401231320230 is a wasteful number, since it uses less digits than its factorization.

13401231320230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103086394791.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13401231320230 its reverse (3202313210431), we get a palindrome (16603544530661).

The spelling of 13401231320230 in words is "thirteen trillion, four hundred one billion, two hundred thirty-one million, three hundred twenty thousand, two hundred thirty".