Base | Representation |
---|---|
bin | 111110011001111001… |
… | …1000001111011111101 |
3 | 110210220121002211201212 |
4 | 1330303303001323331 |
5 | 4143424312021334 |
6 | 141321551414205 |
7 | 12452652501044 |
oct | 1746363017375 |
9 | 423817084655 |
10 | 134013001469 |
11 | 5191a933576 |
12 | 21b80824365 |
13 | c8393c9009 |
14 | 66b444555b |
15 | 3745305ece |
hex | 1f33cc1efd |
134013001469 has 2 divisors, whose sum is σ = 134013001470. Its totient is φ = 134013001468.
The previous prime is 134013001363. The next prime is 134013001483. The reversal of 134013001469 is 964100310431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122963838244 + 11049163225 = 350662^2 + 105115^2 .
It is an emirp because it is prime and its reverse (964100310431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134013001469 - 236 = 65293524733 is a prime.
It is a super-2 number, since 2×1340130014692 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134013001069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006500734 + 67006500735.
It is an arithmetic number, because the mean of its divisors is an integer number (67006500735).
Almost surely, 2134013001469 is an apocalyptic number.
It is an amenable number.
134013001469 is a deficient number, since it is larger than the sum of its proper divisors (1).
134013001469 is an equidigital number, since it uses as much as digits as its factorization.
134013001469 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 134013001469 in words is "one hundred thirty-four billion, thirteen million, one thousand, four hundred sixty-nine".
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