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1340130023521 is a prime number
BaseRepresentation
bin10011100000000101111…
…110010101100001100001
311202010002222001212110121
4103200011332111201201
5133424041241223041
62503351445200241
7165551446151452
oct23400576254141
94663088055417
101340130023521
11477389508893
12197886a00081
13994b20a30a3
1448c11121129
1524cd70427d1
hex13805f95861

1340130023521 has 2 divisors, whose sum is σ = 1340130023522. Its totient is φ = 1340130023520.

The previous prime is 1340130023429. The next prime is 1340130023539. The reversal of 1340130023521 is 1253200310431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1333941841296 + 6188182225 = 1154964^2 + 78665^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340130023521 - 233 = 1331540088929 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340130023621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065011760 + 670065011761.

It is an arithmetic number, because the mean of its divisors is an integer number (670065011761).

Almost surely, 21340130023521 is an apocalyptic number.

It is an amenable number.

1340130023521 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340130023521 is an equidigital number, since it uses as much as digits as its factorization.

1340130023521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1340130023521 its reverse (1253200310431), we get a palindrome (2593330333952).

The spelling of 1340130023521 in words is "one trillion, three hundred forty billion, one hundred thirty million, twenty-three thousand, five hundred twenty-one".