Base | Representation |
---|---|
bin | 10011100000000101111… |
… | …110010101100001100001 |
3 | 11202010002222001212110121 |
4 | 103200011332111201201 |
5 | 133424041241223041 |
6 | 2503351445200241 |
7 | 165551446151452 |
oct | 23400576254141 |
9 | 4663088055417 |
10 | 1340130023521 |
11 | 477389508893 |
12 | 197886a00081 |
13 | 994b20a30a3 |
14 | 48c11121129 |
15 | 24cd70427d1 |
hex | 13805f95861 |
1340130023521 has 2 divisors, whose sum is σ = 1340130023522. Its totient is φ = 1340130023520.
The previous prime is 1340130023429. The next prime is 1340130023539. The reversal of 1340130023521 is 1253200310431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1333941841296 + 6188182225 = 1154964^2 + 78665^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340130023521 - 233 = 1331540088929 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340130023621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065011760 + 670065011761.
It is an arithmetic number, because the mean of its divisors is an integer number (670065011761).
Almost surely, 21340130023521 is an apocalyptic number.
It is an amenable number.
1340130023521 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340130023521 is an equidigital number, since it uses as much as digits as its factorization.
1340130023521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1340130023521 its reverse (1253200310431), we get a palindrome (2593330333952).
The spelling of 1340130023521 in words is "one trillion, three hundred forty billion, one hundred thirty million, twenty-three thousand, five hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •