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1340131999 is a prime number
BaseRepresentation
bin100111111100000…
…1100101010011111
310110101200202111111
41033320030222133
510221033210444
6340551402451
745131635243
oct11770145237
93411622444
101340131999
11628519008
12314983427
1318484991b
14c9daa423
157c9bb234
hex4fe0ca9f

1340131999 has 2 divisors, whose sum is σ = 1340132000. Its totient is φ = 1340131998.

The previous prime is 1340131951. The next prime is 1340132051. The reversal of 1340131999 is 9991310431.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340131999 - 211 = 1340129951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340131909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065999 + 670066000.

It is an arithmetic number, because the mean of its divisors is an integer number (670066000).

Almost surely, 21340131999 is an apocalyptic number.

1340131999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340131999 is an equidigital number, since it uses as much as digits as its factorization.

1340131999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 40.

The square root of 1340131999 is about 36607.8133599919. The cubic root of 1340131999 is about 1102.5099706182.

The spelling of 1340131999 in words is "one billion, three hundred forty million, one hundred thirty-one thousand, nine hundred ninety-nine".