13401333310432 has 48 divisors (see below), whose sum is σ = 27785658700800. Its totient is φ = 6344992275840.

The previous prime is 13401333310429. The next prime is 13401333310439. The reversal of 13401333310432 is 23401333310431.

It is a junction number, because it is equal to n+sod(n) for n = 13401333310394 and 13401333310403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401333310439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3937182 + ... + 6504157.

It is an arithmetic number, because the mean of its divisors is an integer number (578867889600).

Almost surely, 2^{13401333310432} is an apocalyptic number.

It is an amenable number.

13401333310432 is an abundant number, since it is smaller than the sum of its proper divisors (14384325390368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401333310432 is a wasteful number, since it uses less digits than its factorization.

13401333310432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10443479 (or 10443471 counting only the distinct ones).

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13401333310432 its reverse (23401333310431), we get a palindrome (36802666620863).

Subtracting 13401333310432 from its reverse (23401333310431), we obtain a palindrome (9999999999999).

The spelling of 13401333310432 in words is "thirteen trillion, four hundred one billion, three hundred thirty-three million, three hundred ten thousand, four hundred thirty-two".