13401343243133 has 2 divisors, whose sum is σ = 13401343243134. Its totient is φ = 13401343243132.

The previous prime is 13401343243129. The next prime is 13401343243199. The reversal of 13401343243133 is 33134234310431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13400600026489 + 743216644 = 3660683^2 + 27262^2 .

It is an emirp because it is prime and its reverse (33134234310431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13401343243133 - 2² = 13401343243129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13401343243093 and 13401343243102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401343243033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700671621566 + 6700671621567.

It is an arithmetic number, because the mean of its divisors is an integer number (6700671621567).

Almost surely, 2^{13401343243133} is an apocalyptic number.

It is an amenable number.

13401343243133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401343243133 is an equidigital number, since it uses as much as digits as its factorization.

13401343243133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 13401343243133 its reverse (33134234310431), we get a palindrome (46535577553564).

The spelling of 13401343243133 in words is "thirteen trillion, four hundred one billion, three hundred forty-three million, two hundred forty-three thousand, one hundred thirty-three".