13401345040 has 20 divisors (see below), whose sum is σ = 31158127404. Its totient is φ = 5360537984.

The previous prime is 13401344977. The next prime is 13401345049. The reversal of 13401345040 is 4054310431.

It can be written as a sum of positive squares in 2 ways, for example, as 3869337616 + 9532007424 = 62204^2 + 97632^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a super-2 number, since 2×13401345040² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13401344996 and 13401345014.

It is not an unprimeable number, because it can be changed into a prime (13401345049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83758327 + ... + 83758486.

Almost surely, 2^13401345040 is an apocalyptic number.

13401345040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13401345040 is an abundant number, since it is smaller than the sum of its proper divisors (17756782364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401345040 is a wasteful number, since it uses less digits than its factorization.

13401345040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167516826 (or 167516820 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13401345040 its reverse (4054310431), we get a palindrome (17455655471).

The spelling of 13401345040 in words is "thirteen billion, four hundred one million, three hundred forty-five thousand, forty".