1340141230122 has 64 divisors (see below), whose sum is σ = 2930151988224. Its totient is φ = 406782443520.

The previous prime is 1340141230093. The next prime is 1340141230163. The reversal of 1340141230122 is 2210321410431.

It is a super-3 number, since 3×1340141230122³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340141230092 and 1340141230101.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14730678 + ... + 14821374.

It is an arithmetic number, because the mean of its divisors is an integer number (45783624816).

Almost surely, 2^{1340141230122} is an apocalyptic number.

1340141230122 is an abundant number, since it is smaller than the sum of its proper divisors (1590010758102).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340141230122 is a wasteful number, since it uses less digits than its factorization.

1340141230122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95423.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1340141230122 its reverse (2210321410431), we get a palindrome (3550462640553).

The spelling of 1340141230122 in words is "one trillion, three hundred forty billion, one hundred forty-one million, two hundred thirty thousand, one hundred twenty-two".