1340143040020 has 12 divisors (see below), whose sum is σ = 2814300384084. Its totient is φ = 536057216000.

The previous prime is 1340143040017. The next prime is 1340143040023. The reversal of 1340143040020 is 200403410431.

It is an interprime number because it is at equal distance from previous prime (1340143040017) and next prime (1340143040023).

It can be written as a sum of positive squares in 2 ways, for example, as 179399685136 + 1160743354884 = 423556^2 + 1077378^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1340143039973 and 1340143040000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340143040023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33503575981 + ... + 33503576020.

It is an arithmetic number, because the mean of its divisors is an integer number (234525032007).

Almost surely, 2^{1340143040020} is an apocalyptic number.

1340143040020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1340143040020 is an abundant number, since it is smaller than the sum of its proper divisors (1474157344064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340143040020 is a wasteful number, since it uses less digits than its factorization.

1340143040020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67007152010 (or 67007152008 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1340143040020 its reverse (200403410431), we get a palindrome (1540546450451).

The spelling of 1340143040020 in words is "one trillion, three hundred forty billion, one hundred forty-three million, forty thousand, twenty".