Base | Representation |
---|---|
bin | 10011100000000110101… |
… | …111111111011000010111 |
3 | 11202010010212120011202021 |
4 | 103200012233333120113 |
5 | 133424103104240043 |
6 | 2503353032154011 |
7 | 165551664613444 |
oct | 23400657773027 |
9 | 4663125504667 |
10 | 1340143040023 |
11 | 477395899327 |
12 | 19788b238907 |
13 | 994b49ac968 |
14 | 48c12b4c9cb |
15 | 24cd82643ed |
hex | 13806bff617 |
1340143040023 has 2 divisors, whose sum is σ = 1340143040024. Its totient is φ = 1340143040022.
The previous prime is 1340143040017. The next prime is 1340143040029. The reversal of 1340143040023 is 3200403410431.
It is a balanced prime because it is at equal distance from previous prime (1340143040017) and next prime (1340143040029).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340143040023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340143040023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340143040029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670071520011 + 670071520012.
It is an arithmetic number, because the mean of its divisors is an integer number (670071520012).
Almost surely, 21340143040023 is an apocalyptic number.
1340143040023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340143040023 is an equidigital number, since it uses as much as digits as its factorization.
1340143040023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 1340143040023 its reverse (3200403410431), we get a palindrome (4540546450454).
The spelling of 1340143040023 in words is "one trillion, three hundred forty billion, one hundred forty-three million, forty thousand, twenty-three".
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