Search a number
-
+
134015381 is a prime number
BaseRepresentation
bin1111111110011…
…10100110010101
3100100011200112122
413333032212111
5233301443011
621144225325
73215053253
oct777164625
9310150478
10134015381
1169714815
1238a6b245
13219c3356
1413b275d3
15bb733db
hex7fce995

134015381 has 2 divisors, whose sum is σ = 134015382. Its totient is φ = 134015380.

The previous prime is 134015359. The next prime is 134015383. The reversal of 134015381 is 183510431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91374481 + 42640900 = 9559^2 + 6530^2 .

It is a cyclic number.

It is not a de Polignac number, because 134015381 - 222 = 129821077 is a prime.

It is a super-2 number, since 2×1340153812 = 35920244689150322, which contains 22 as substring.

Together with 134015383, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134015381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134015383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007690 + 67007691.

It is an arithmetic number, because the mean of its divisors is an integer number (67007691).

Almost surely, 2134015381 is an apocalyptic number.

It is an amenable number.

134015381 is a deficient number, since it is larger than the sum of its proper divisors (1).

134015381 is an equidigital number, since it uses as much as digits as its factorization.

134015381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 134015381 is about 11576.5012417397. The cubic root of 134015381 is about 511.7425730749.

The spelling of 134015381 in words is "one hundred thirty-four million, fifteen thousand, three hundred eighty-one".