Base | Representation |
---|---|
bin | 11000111101101001… |
… | …00111010110001111 |
3 | 1021121000020200220122 |
4 | 30132310213112033 |
5 | 204421403323043 |
6 | 10053511335155 |
7 | 653054133302 |
oct | 143664472617 |
9 | 37530220818 |
10 | 13402011023 |
11 | 57580a4275 |
12 | 27203814bb |
13 | 135776874b |
14 | 911cd4b39 |
15 | 5368b1368 |
hex | 31ed2758f |
13402011023 has 2 divisors, whose sum is σ = 13402011024. Its totient is φ = 13402011022.
The previous prime is 13402011017. The next prime is 13402011041. The reversal of 13402011023 is 32011020431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13402011023 - 218 = 13401748879 is a prime.
It is a super-2 number, since 2×134020110232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13402010992 and 13402011010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402011043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701005511 + 6701005512.
It is an arithmetic number, because the mean of its divisors is an integer number (6701005512).
Almost surely, 213402011023 is an apocalyptic number.
13402011023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402011023 is an equidigital number, since it uses as much as digits as its factorization.
13402011023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13402011023 its reverse (32011020431), we get a palindrome (45413031454).
The spelling of 13402011023 in words is "thirteen billion, four hundred two million, eleven thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •