13402011041 has 2 divisors, whose sum is σ = 13402011042. Its totient is φ = 13402011040.

The previous prime is 13402011023. The next prime is 13402011043. The reversal of 13402011041 is 14011020431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9580298641 + 3821712400 = 97879^2 + 61820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13402011041 is a prime.

It is a super-2 number, since 2×13402011041² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13402011043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13402011043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701005520 + 6701005521.

It is an arithmetic number, because the mean of its divisors is an integer number (6701005521).

Almost surely, 2^13402011041 is an apocalyptic number.

It is an amenable number.

13402011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402011041 is an equidigital number, since it uses as much as digits as its factorization.

13402011041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 13402011041 its reverse (14011020431), we get a palindrome (27413031472).

The spelling of 13402011041 in words is "thirteen billion, four hundred two million, eleven thousand, forty-one".