134020151 has 2 divisors, whose sum is σ = 134020152. Its totient is φ = 134020150.

The previous prime is 134020123. The next prime is 134020153. The reversal of 134020151 is 151020431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134020151 - 2⁶ = 134020087 is a prime.

It is a super-2 number, since 2×134020151² = 35922801748125602, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 134020153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134020153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010075 + 67010076.

It is an arithmetic number, because the mean of its divisors is an integer number (67010076).

Almost surely, 2^134020151 is an apocalyptic number.

134020151 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020151 is an equidigital number, since it uses as much as digits as its factorization.

134020151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 134020151 is about 11576.7072607024. The cubic root of 134020151 is about 511.7486444753.

Adding to 134020151 its reverse (151020431), we get a palindrome (285040582).

The spelling of 134020151 in words is "one hundred thirty-four million, twenty thousand, one hundred fifty-one".