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134020181 is a prime number
BaseRepresentation
bin1111111110011…
…11110001010101
3100100011221010102
413333033301111
5233302121211
621144303445
73215103251
oct777176125
9310157112
10134020181
1169718389
1238a71b85
13219c55a9
1413b29261
15bb74a3b
hex7fcfc55

134020181 has 2 divisors, whose sum is σ = 134020182. Its totient is φ = 134020180.

The previous prime is 134020169. The next prime is 134020213. The reversal of 134020181 is 181020431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132480100 + 1540081 = 11510^2 + 1241^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134020181 is a prime.

It is a super-2 number, since 2×1340201812 = 35922817830545522, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134020151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010090 + 67010091.

It is an arithmetic number, because the mean of its divisors is an integer number (67010091).

Almost surely, 2134020181 is an apocalyptic number.

It is an amenable number.

134020181 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020181 is an equidigital number, since it uses as much as digits as its factorization.

134020181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

The square root of 134020181 is about 11576.7085564076. The cubic root of 134020181 is about 511.7486826598.

The spelling of 134020181 in words is "one hundred thirty-four million, twenty thousand, one hundred eighty-one".