Base | Representation |
---|---|
bin | 11110011110010000111001… |
… | …010100010001100010101111 |
3 | 122120112021221100211002001122 |
4 | 132132100321110101202233 |
5 | 120031300224001323211 |
6 | 1153012241510531155 |
7 | 40141464214241306 |
oct | 3636207124214257 |
9 | 576467840732048 |
10 | 134021121120431 |
11 | 39781046a49226 |
12 | 13046236366abb |
13 | 59a21a30c25cc |
14 | 251492a65d43d |
15 | 10762e49286db |
hex | 79e4395118af |
134021121120431 has 2 divisors, whose sum is σ = 134021121120432. Its totient is φ = 134021121120430.
The previous prime is 134021121120421. The next prime is 134021121120443.
It is a happy number.
134021121120431 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 134021121120431 - 222 = 134021116926127 is a prime.
It is a super-2 number, since 2×1340211211204312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 134021121120431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134021121120421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010560560215 + 67010560560216.
It is an arithmetic number, because the mean of its divisors is an integer number (67010560560216).
Almost surely, 2134021121120431 is an apocalyptic number.
134021121120431 is a deficient number, since it is larger than the sum of its proper divisors (1).
134021121120431 is an equidigital number, since it uses as much as digits as its factorization.
134021121120431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
The spelling of 134021121120431 in words is "one hundred thirty-four trillion, twenty-one billion, one hundred twenty-one million, one hundred twenty thousand, four hundred thirty-one".
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