Base | Representation |
---|---|
bin | 11110011110010000111111… |
… | …111011101000001010101110 |
3 | 122120112022020002122102102120 |
4 | 132132100333323220022232 |
5 | 120031300440404200024 |
6 | 1153012300513333410 |
7 | 40141500032453040 |
oct | 3636207773501256 |
9 | 576468202572376 |
10 | 134021232100014 |
11 | 397810a3659896 |
12 | 13046267567266 |
13 | 59a21c00ab7bc |
14 | 251493b2aba90 |
15 | 10762ee54b479 |
hex | 79e43fee82ae |
134021232100014 has 32 divisors (see below), whose sum is σ = 306748770236160. Its totient is φ = 38239964920512.
The previous prime is 134021232100013. The next prime is 134021232100057. The reversal of 134021232100014 is 410001232120431.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134021232100013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2158955239 + ... + 2159017314.
It is an arithmetic number, because the mean of its divisors is an integer number (9585899069880).
Almost surely, 2134021232100014 is an apocalyptic number.
134021232100014 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
134021232100014 is an abundant number, since it is smaller than the sum of its proper divisors (172727538136146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134021232100014 is a wasteful number, since it uses less digits than its factorization.
134021232100014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4317973304.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 134021232100014 its reverse (410001232120431), we get a palindrome (544022464220445).
The spelling of 134021232100014 in words is "one hundred thirty-four trillion, twenty-one billion, two hundred thirty-two million, one hundred thousand, fourteen".
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