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13402219046141 is a prime number
BaseRepresentation
bin1100001100000111001010…
…0000010110010011111101
31202110020110200121010022102
43003001302200112103331
53224040221033434031
644300521110354445
72552164324155602
oct303016240262375
952406420533272
1013402219046141
1142a7938290322
12160553405ba25
13762a92c662c3
14344956bc26a9
15183950cb07cb
hexc30728164fd

13402219046141 has 2 divisors, whose sum is σ = 13402219046142. Its totient is φ = 13402219046140.

The previous prime is 13402219046113. The next prime is 13402219046189. The reversal of 13402219046141 is 14164091220431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13271055558916 + 131163487225 = 3642946^2 + 362165^2 .

It is a cyclic number.

It is not a de Polignac number, because 13402219046141 - 226 = 13402151937277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13402219046095 and 13402219046104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13402219040141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701109523070 + 6701109523071.

It is an arithmetic number, because the mean of its divisors is an integer number (6701109523071).

Almost surely, 213402219046141 is an apocalyptic number.

It is an amenable number.

13402219046141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402219046141 is an equidigital number, since it uses as much as digits as its factorization.

13402219046141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 13402219046141 in words is "thirteen trillion, four hundred two billion, two hundred nineteen million, forty-six thousand, one hundred forty-one".