Base | Representation |
---|---|
bin | 1100001100000111001010… |
… | …1000010110010011111101 |
3 | 1202110020110211112200001201 |
4 | 3003001302220112103331 |
5 | 3224040222103041133 |
6 | 44300521223335501 |
7 | 2552164351042003 |
oct | 303016250262375 |
9 | 52406424480051 |
10 | 13402221143293 |
11 | 42a7939492a04 |
12 | 16055348b1591 |
13 | 762a9351ba18 |
14 | 3449571aaa73 |
15 | 183951076d7d |
hex | c3072a164fd |
13402221143293 has 2 divisors, whose sum is σ = 13402221143294. Its totient is φ = 13402221143292.
The previous prime is 13402221143219. The next prime is 13402221143303. The reversal of 13402221143293 is 39234112220431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11002999823929 + 2399221319364 = 3317077^2 + 1548942^2 .
It is a cyclic number.
It is not a de Polignac number, because 13402221143293 - 221 = 13402219046141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402221173293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701110571646 + 6701110571647.
It is an arithmetic number, because the mean of its divisors is an integer number (6701110571647).
Almost surely, 213402221143293 is an apocalyptic number.
It is an amenable number.
13402221143293 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402221143293 is an equidigital number, since it uses as much as digits as its factorization.
13402221143293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 37.
The spelling of 13402221143293 in words is "thirteen trillion, four hundred two billion, two hundred twenty-one million, one hundred forty-three thousand, two hundred ninety-three".
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