Base | Representation |
---|---|
bin | 1100001100000111001010… |
… | …1001010111111111011010 |
3 | 1202110020110212001100002110 |
4 | 3003001302221113333122 |
5 | 3224040222140143224 |
6 | 44300521233213150 |
7 | 2552164353242220 |
oct | 303016251277732 |
9 | 52406425040073 |
10 | 13402221412314 |
11 | 42a7939657039 |
12 | 1605534a011b6 |
13 | 762a935b42c7 |
14 | 34495723ab10 |
15 | 1839510cb929 |
hex | c3072a57fda |
13402221412314 has 64 divisors (see below), whose sum is σ = 31003786598400. Its totient is φ = 3783141402048.
The previous prime is 13402221412313. The next prime is 13402221412319. The reversal of 13402221412314 is 41321412220431.
It is a happy number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13402221412313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2629774 + ... + 5806905.
It is an arithmetic number, because the mean of its divisors is an integer number (484434165600).
Almost surely, 213402221412314 is an apocalyptic number.
13402221412314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13402221412314 is an abundant number, since it is smaller than the sum of its proper divisors (17601565186086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402221412314 is a wasteful number, since it uses less digits than its factorization.
13402221412314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8437147.
The product of its (nonzero) digits is 9216, while the sum is 30.
Adding to 13402221412314 its reverse (41321412220431), we get a palindrome (54723633632745).
The spelling of 13402221412314 in words is "thirteen trillion, four hundred two billion, two hundred twenty-one million, four hundred twelve thousand, three hundred fourteen".
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