Base | Representation |
---|---|
bin | 10011100000001011101… |
… | …001110011101000100101 |
3 | 11202010100121100200020220 |
4 | 103200023221303220211 |
5 | 133424240134231000 |
6 | 2503405131314553 |
7 | 165554014062420 |
oct | 23401351635045 |
9 | 4663317320226 |
10 | 1340225305125 |
11 | 477428277313 |
12 | 1978b28aba59 |
13 | 994c8a54035 |
14 | 48c1da449b7 |
15 | 24ce05b41a0 |
hex | 1380ba73a25 |
1340225305125 has 64 divisors (see below), whose sum is σ = 2549069512704. Its totient is φ = 612591758400.
The previous prime is 1340225305117. The next prime is 1340225305151. The reversal of 1340225305125 is 5215035220431.
It is not a de Polignac number, because 1340225305125 - 23 = 1340225305117 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22143154 + ... + 22203596.
It is an arithmetic number, because the mean of its divisors is an integer number (39829211136).
Almost surely, 21340225305125 is an apocalyptic number.
1340225305125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1340225305125 is a deficient number, since it is larger than the sum of its proper divisors (1208844207579).
1340225305125 is an equidigital number, since it uses as much as digits as its factorization.
1340225305125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68915 (or 68905 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 1340225305125 in words is "one trillion, three hundred forty billion, two hundred twenty-five million, three hundred five thousand, one hundred twenty-five".
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