Base | Representation |
---|---|
bin | 1100001100000111111010… |
… | …0011001111011111111011 |
3 | 1202110020222202212002222102 |
4 | 3003001332203033133323 |
5 | 3224041124302200014 |
6 | 44300553130014015 |
7 | 2552202326646206 |
oct | 303017643173773 |
9 | 52406882762872 |
10 | 13402421131259 |
11 | 42a7a31367916 |
12 | 160558b87730b |
13 | 762ac5aa06b4 |
14 | 34497598893d |
15 | 1839638cc8de |
hex | c307e8cf7fb |
13402421131259 has 2 divisors, whose sum is σ = 13402421131260. Its totient is φ = 13402421131258.
The previous prime is 13402421131243. The next prime is 13402421131331. The reversal of 13402421131259 is 95213112420431.
It is a weak prime.
It is an emirp because it is prime and its reverse (95213112420431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13402421131259 - 24 = 13402421131243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13402421131219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701210565629 + 6701210565630.
It is an arithmetic number, because the mean of its divisors is an integer number (6701210565630).
Almost surely, 213402421131259 is an apocalyptic number.
13402421131259 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402421131259 is an equidigital number, since it uses as much as digits as its factorization.
13402421131259 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 38.
The spelling of 13402421131259 in words is "thirteen trillion, four hundred two billion, four hundred twenty-one million, one hundred thirty-one thousand, two hundred fifty-nine".
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