Base | Representation |
---|---|
bin | 1100001100000111111010… |
… | …0011001111100001000011 |
3 | 1202110020222202212010002002 |
4 | 3003001332203033201003 |
5 | 3224041124302200311 |
6 | 44300553130014215 |
7 | 2552202326646341 |
oct | 303017643174103 |
9 | 52406882763062 |
10 | 13402421131331 |
11 | 42a7a31367981 |
12 | 160558b87736b |
13 | 762ac5aa073b |
14 | 344975988991 |
15 | 1839638cc93b |
hex | c307e8cf843 |
13402421131331 has 2 divisors, whose sum is σ = 13402421131332. Its totient is φ = 13402421131330.
The previous prime is 13402421131259. The next prime is 13402421131343. The reversal of 13402421131331 is 13313112420431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13402421131331 - 234 = 13385241262147 is a prime.
It is a super-2 number, since 2×134024211313312 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13402421131294 and 13402421131303.
It is not a weakly prime, because it can be changed into another prime (13402421131381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701210565665 + 6701210565666.
It is an arithmetic number, because the mean of its divisors is an integer number (6701210565666).
Almost surely, 213402421131331 is an apocalyptic number.
13402421131331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402421131331 is an equidigital number, since it uses as much as digits as its factorization.
13402421131331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13402421131331 its reverse (13313112420431), we get a palindrome (26715533551762).
The spelling of 13402421131331 in words is "thirteen trillion, four hundred two billion, four hundred twenty-one million, one hundred thirty-one thousand, three hundred thirty-one".
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