Base | Representation |
---|---|
bin | 1100001100000111111010… |
… | …0011001111100001000010 |
3 | 1202110020222202212010002001 |
4 | 3003001332203033201002 |
5 | 3224041124302200310 |
6 | 44300553130014214 |
7 | 2552202326646340 |
oct | 303017643174102 |
9 | 52406882763061 |
10 | 13402421131330 |
11 | 42a7a31367980 |
12 | 160558b87736a |
13 | 762ac5aa073a |
14 | 344975988990 |
15 | 1839638cc93a |
hex | c307e8cf842 |
13402421131330 has 64 divisors (see below), whose sum is σ = 30268696004352. Its totient is φ = 4150770474240.
The previous prime is 13402421131259. The next prime is 13402421131331. The reversal of 13402421131330 is 3313112420431.
It is not an unprimeable number, because it can be changed into a prime (13402421131331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55311409 + ... + 55553188.
It is an arithmetic number, because the mean of its divisors is an integer number (472948375068).
Almost surely, 213402421131330 is an apocalyptic number.
13402421131330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13402421131330 is an abundant number, since it is smaller than the sum of its proper divisors (16866274873022).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402421131330 is a wasteful number, since it uses less digits than its factorization.
13402421131330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110864779.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13402421131330 its reverse (3313112420431), we get a palindrome (16715533551761).
The spelling of 13402421131330 in words is "thirteen trillion, four hundred two billion, four hundred twenty-one million, one hundred thirty-one thousand, three hundred thirty".
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