Search a number
-
+
134024211320 = 2353350605283
BaseRepresentation
bin111110011010001110…
…1110010101101111000
3110210221101012100202112
41330310131302231320
54143440144230240
6141323031551452
712453146666606
oct1746435625570
9423841170675
10134024211320
115192619a70a
1221b8452b588
13c83b82246c
1466b5b22876
1537462bc665
hex1f34772b78

134024211320 has 16 divisors (see below), whose sum is σ = 301554475560. Its totient is φ = 53609684512.

The previous prime is 134024211319. The next prime is 134024211337. The reversal of 134024211320 is 23112420431.

It is a super-2 number, since 2×1340242113202 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1675302602 + ... + 1675302681.

Almost surely, 2134024211320 is an apocalyptic number.

134024211320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134024211320 is an abundant number, since it is smaller than the sum of its proper divisors (167530264240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134024211320 is a wasteful number, since it uses less digits than its factorization.

134024211320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3350605294 (or 3350605290 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 134024211320 its reverse (23112420431), we get a palindrome (157136631751).

The spelling of 134024211320 in words is "one hundred thirty-four billion, twenty-four million, two hundred eleven thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 3350605283 6701210566 13402421132 16753026415 26804842264 33506052830 67012105660 134024211320