Base | Representation |
---|---|
bin | 111110011010001110… |
… | …1110010101101110111 |
3 | 110210221101012100202111 |
4 | 1330310131302231313 |
5 | 4143440144230234 |
6 | 141323031551451 |
7 | 12453146666605 |
oct | 1746435625567 |
9 | 423841170674 |
10 | 134024211319 |
11 | 5192619a709 |
12 | 21b8452b587 |
13 | c83b82246b |
14 | 66b5b22875 |
15 | 37462bc664 |
hex | 1f34772b77 |
134024211319 has 2 divisors, whose sum is σ = 134024211320. Its totient is φ = 134024211318.
The previous prime is 134024211317. The next prime is 134024211337. The reversal of 134024211319 is 913112420431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134024211319 - 21 = 134024211317 is a prime.
It is a super-2 number, since 2×1340242113192 (a number of 23 digits) contains 22 as substring.
Together with 134024211317, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134024211311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012105659 + 67012105660.
It is an arithmetic number, because the mean of its divisors is an integer number (67012105660).
Almost surely, 2134024211319 is an apocalyptic number.
134024211319 is a deficient number, since it is larger than the sum of its proper divisors (1).
134024211319 is an equidigital number, since it uses as much as digits as its factorization.
134024211319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 134024211319 in words is "one hundred thirty-four billion, twenty-four million, two hundred eleven thousand, three hundred nineteen".
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