Base | Representation |
---|---|
bin | 11110011110010100100010… |
… | …011011110111000001110011 |
3 | 122120112200000221012112000212 |
4 | 132132110202123313001303 |
5 | 120031331231220402212 |
6 | 1153014125542534335 |
7 | 40141663145000453 |
oct | 3636244233670163 |
9 | 576480027175025 |
10 | 134025032200307 |
11 | 39782773719446 |
12 | 13046b481373ab |
13 | 59a267747c761 |
14 | 2514bbbc67d63 |
15 | 1076472e86e22 |
hex | 79e5226f7073 |
134025032200307 has 2 divisors, whose sum is σ = 134025032200308. Its totient is φ = 134025032200306.
The previous prime is 134025032200303. The next prime is 134025032200313. The reversal of 134025032200307 is 703002230520431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (703002230520431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134025032200307 - 22 = 134025032200303 is a prime.
It is not a weakly prime, because it can be changed into another prime (134025032200303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012516100153 + 67012516100154.
It is an arithmetic number, because the mean of its divisors is an integer number (67012516100154).
Almost surely, 2134025032200307 is an apocalyptic number.
134025032200307 is a deficient number, since it is larger than the sum of its proper divisors (1).
134025032200307 is an equidigital number, since it uses as much as digits as its factorization.
134025032200307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 32.
Adding to 134025032200307 its reverse (703002230520431), we get a palindrome (837027262720738).
The spelling of 134025032200307 in words is "one hundred thirty-four trillion, twenty-five billion, thirty-two million, two hundred thousand, three hundred seven".
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