Base | Representation |
---|---|
bin | 10011100000010001110… |
… | …001101111100011000001 |
3 | 11202010121202200121010102 |
4 | 103200101301233203001 |
5 | 133424442440030313 |
6 | 2503423241412145 |
7 | 165556402302644 |
oct | 23402161574301 |
9 | 4663552617112 |
10 | 1340328048833 |
11 | 477480272174 |
12 | 19792119a055 |
13 | 99514118627 |
14 | 48c2d54ba5b |
15 | 24ce960ba58 |
hex | 13811c6f8c1 |
1340328048833 has 2 divisors, whose sum is σ = 1340328048834. Its totient is φ = 1340328048832.
The previous prime is 1340328048797. The next prime is 1340328048869. The reversal of 1340328048833 is 3388408230431.
It is a balanced prime because it is at equal distance from previous prime (1340328048797) and next prime (1340328048869).
It can be written as a sum of positive squares in only one way, i.e., 1337892428929 + 2435619904 = 1156673^2 + 49352^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340328048833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340327048833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670164024416 + 670164024417.
It is an arithmetic number, because the mean of its divisors is an integer number (670164024417).
Almost surely, 21340328048833 is an apocalyptic number.
It is an amenable number.
1340328048833 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340328048833 is an equidigital number, since it uses as much as digits as its factorization.
1340328048833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1327104, while the sum is 47.
The spelling of 1340328048833 in words is "one trillion, three hundred forty billion, three hundred twenty-eight million, forty-eight thousand, eight hundred thirty-three".
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